Asked by Candy
y= 2sin^2 x
y=1- sinx
find values of x inthe interval 0<x<360
if
2sin^x = 1-sinx
this can be arranged into the quadratic.
2sin^2 x + sin x -1=0
(2sinx -1)(sinx + 1)=0
or sinx = 1/2 and sin x=-1
y=1- sinx
find values of x inthe interval 0<x<360
if
2sin^x = 1-sinx
this can be arranged into the quadratic.
2sin^2 x + sin x -1=0
(2sinx -1)(sinx + 1)=0
or sinx = 1/2 and sin x=-1
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