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y= 2sin^2 x y=1- sinx
y= 2sin^2 x
y=1- sinx find values of x inthe interval 0<x<360 if 2sin^x = 1-sinx this can be arranged into the quadratic. 2sin^2
0 answers
asked by
Candy
648 views
the problem is
2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
3 answers
asked by
alex
863 views
Prove:
sin2x / 1 - cos2x = cotx My Attempt: LS: = 2sinxcosx / - 1 - (1 - 2sin^2x) = 2sinxcosx / - 1 + 2sin^2x = cosx / sinx - 1 =
5 answers
asked by
Anonymous
1,442 views
Hello! Can someone please check and see if I did this right? Thanks! :)
Directions: Find the exact solutions of the equation in
1 answer
asked by
Maggie
831 views
I need help solving for all solutions for this problem:
cos 2x+ sin x= 0 I substituted cos 2x for cos^2x-sin^2x So it became
1 answer
asked by
Martha
631 views
I was given 21 questions for homework and I can't get the last few no matter how hard and how many times I try.
17. Sinx-1/sinx+1
5 answers
asked by
Kim
1,137 views
tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
0 answers
asked by
shan
978 views
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
3 answers
asked by
Anonymous
938 views
(sinx - cosx)(sinx + cosx) = 2sin^2x -1
I need some tips on trigonometric identities. Why shouldn't I just turn (sinx + cosx)
2 answers
asked by
Anonymous
1,420 views
solve each equation for 0=/<x=/<2pi
sin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
7 answers
asked by
sh
947 views