x^(-2) = 9
Since, x^(-2) = 1/x^2
1/x^2 = 9
Multiply both sides by x^2
1 = 9x^2
1/9 = x^2
square root of both sides
+ - 1/3 = x
x^(-2) = 9
solve for x
Steps too
I first squared the x on both sides and I was left with x^(-1) = -3,3
but then what would the answer be for x?
the answer is supposed to be 1/3, -1/3 but I don't know why
2 answers
Meant to comment,
If you square x^-2,
x^-2 * x^-2 = x-4 = 1/x^4
1/^4 = 81
square root of both sides
1/x^2 = 9
You are back to the above.
If you square x^-2,
x^-2 * x^-2 = x-4 = 1/x^4
1/^4 = 81
square root of both sides
1/x^2 = 9
You are back to the above.
7 answers