writing linear eqautions from standard form to slope-intercept form

Question

x+8y=0

Answer 1

To convert the equation from standard form (Ax + By = C) to slope-intercept form (y = mx + b), you need to solve for \( y \).

Given the equation:

\[ x + 8y = 0 \]

Follow these steps:

1. Isolate the \( y \) term:

   Subtract \( x \) from both sides: \[ 8y = -x \]

2. Solve for \( y \):

   Divide both sides by 8: \[ y = -\frac{1}{8}x \]

Now, the equation is in slope-intercept form \( y = mx + b \), where:

• The slope \( m = -\frac{1}{8} \)
• The y-intercept \( b = 0 \)

So the final slope-intercept form of the equation is:

\[ y = -\frac{1}{8}x \]