writing linear eqautions from standard form to slope-intercept form

x+5y=-10

1 answer

To convert the equation from standard form \( Ax + By = C \) to slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept, you'll want to solve for \( y \).

Starting with the equation:

\[ x + 5y = -10 \]

Follow these steps:

  1. Isolate the term involving \( y \):

    Subtract \( x \) from both sides:

    \[ 5y = -10 - x \]

  2. Rearrange the equation:

    You can rearrange the right side to make it more recognizable:

    \[ 5y = -x - 10 \]

  3. Solve for \( y \):

    Divide every term by 5:

    \[ y = -\frac{1}{5}x - 2 \]

Now, the equation is in slope-intercept form:

\[ y = -\frac{1}{5}x - 2 \]

From this, you can see that the slope \( m \) is \( -\frac{1}{5} \) and the y-intercept \( b \) is \( -2 \).

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