Question

Write the standard form of the equation of a circle that passes through the points at (0,8) (8,0) and (16,8). Then identify the center and radius of the circle.

(x-8)^2 + (y-8)^2 = 64
(x^2 / 64) + (y^2 / 64) = 64
center=(8,8)
radius=8

I got it wrong don't know how

Answer 1

(x-8)^2 + (y-8)^2 = 64
fine

(x^2 / 64) + (y^2 / 64) = 64
but where did you get this??????

center=(8,8)
fine
radius=8
fine

Answer 2

You will have to write the equation
(x-h)^2+(y-k)^2=r^2
for the three sets of points given. Then solve for h, k, r

It is ugly but solvable.