the distance from (-6,-8) to (0,0) is 10. So,
(x+6)^2 + (y+8)^2 = 10^2
Write the standard equation for the circle center (-6,-8), that passes through (0,0).
I know that the formula would leave the 1qstr part as
(x+6)+(y+8)
I'm not sure about the radius when it goes through (0,0)
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