Write the standard equation for the circle center (-6,-8), that passes through (0,0).

Question

I know that the formula would leave the 1qstr part as

(x+6)+(y+8)

I'm not sure about the radius when it goes through (0,0)

Answer 1

the distance from (-6,-8) to (0,0) is 10. So,

(x+6)^2 + (y+8)^2 = 10^2