Since the slope-intercept form of an equation is y = mx + b, where m is the slope and b is the y-intercept, we can substitute the given slope (-3/4) for the value of m and the coordinates of the point (-4, -3) for the values of x and y.
So, the equation becomes:
-3 = (-3/4)(-4) + b
Simplifying -3/4 * -4 = 12/4 = 3, the equation becomes:
-3 = 3 + b
Now, we can isolate b by subtracting 3 from both sides of the equation:
-3 - 3 = 3 + b - 3
-6 = b
Therefore, the slope-intercept form equation for the line with a slope of -3/4 that passes through the point (-4, -3) is:
y = (-3/4)x - 6
Write the slope-intercept form equation for a line with slope of -3/4 that passes through the point (-4, -3)
y = __________ x + _________
1 answer
1 answer