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Use slope-intercept form to write the equation of a line that has a slope of −3 and passes through the point (1, −5).

Use the drop-down menus to select the proper value for each variable that is substituted into the slope-intercept equation.

y =

x =

m =

1 answer

To write the equation of a line in slope-intercept form (y = mx + b), you need the slope (m) and the y-intercept (b). You've provided the slope as -3 and a point (1, -5) through which the line passes.

  1. Start with the slope-intercept form: \[ y = mx + b \]

  2. Substitute the value of the slope (m = -3) into the equation: \[ y = -3x + b \]

  3. Now, use the point (1, -5) to find the value of b. Substitute x = 1 and y = -5 into the equation: \[ -5 = -3(1) + b \]

  4. Solve for b: \[ -5 = -3 + b \] \[ b = -5 + 3 \] \[ b = -2 \]

  5. Now substitute b back into the equation: \[ y = -3x - 2 \]

So, using the drop-down menus, the values are:

  • For \( y \) = \(-3x - 2\)
  • For \( x \) = 1
  • For \( m \) = -3

The final equation of the line is:

\[ y = -3x - 2 \]