Write the net ionic equation for the following reaction :
Na3SO4(aq) + Ba(NO3)2(aq) —> BaSO4 (s) + 2 NaNO3(aq)
3 answers
Ba++ + SO4-- >> BaSO4 (s)
You made an error; it's Na2SO4.
2Na^+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2NO3^-(aq) ==> BaSO4(s) + 2Na^+(aq) + 2NO3^-(aq)
I have written the complete ionic equation above. To make it into a net ionic equation, cancel those ions that appear on both sides. The net ionic equation is what is left.For example, I see 2Na^+(aq) on both sides so cancel those. Etc. I'll check your final answer is you will post it.
2Na^+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2NO3^-(aq) ==> BaSO4(s) + 2Na^+(aq) + 2NO3^-(aq)
I have written the complete ionic equation above. To make it into a net ionic equation, cancel those ions that appear on both sides. The net ionic equation is what is left.For example, I see 2Na^+(aq) on both sides so cancel those. Etc. I'll check your final answer is you will post it.
Yes my bad Na2SO4. So would the answer be Ba(NO3)2 (aq) -> BaSO4 (s)
1 answer