Ag+ (aq) 3NO3- (aq) 3Na+ (aq)3Cl- (aq) -> AgCl3 (s) 3Na+ 3NO3- (aq)
Net: Ag+ (aq) + 3Cl (aq) -> AgCl3 (s)
Write the net ionic equation for silver nitrate and sodium chloride.
I only know how to do it when it deals with elements, not compound.
3 answers
Most of the above is garbage. For solution.
AgNO3(aq) + NaCl(aq) ==> AgCl(s) + NaNO3
Then rewrite the molecular equation as ions if the molecules are ionic and soluble. If a solid, write it as the molecule. Add (aq) after each except AgCl.
Ag^+ + NO3^- + Na^+ + Cl^- ==>AgCl(s) + Na^+ + NO3^-
Now cancel the ions on each side that are common, in this case that will be NO3^- and Na^+.
And what is left is the net ionic equation.
Ag^+(aq) + Cl^-(aq) ==> AgCl(s)
AgNO3(aq) + NaCl(aq) ==> AgCl(s) + NaNO3
Then rewrite the molecular equation as ions if the molecules are ionic and soluble. If a solid, write it as the molecule. Add (aq) after each except AgCl.
Ag^+ + NO3^- + Na^+ + Cl^- ==>AgCl(s) + Na^+ + NO3^-
Now cancel the ions on each side that are common, in this case that will be NO3^- and Na^+.
And what is left is the net ionic equation.
Ag^+(aq) + Cl^-(aq) ==> AgCl(s)
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