CaCl2(aq) + K2SO4(aq) ==> CaSO4 + 2KCl
Ca^2+(aq) + 2Cl^-(aq) + 2K^+(aq) + [SO4]^2-(aq) ==> CaSO4(s) + 2K^+(aq) + 2Cl^-(aq) is the total ionic equation.
To make that into the net ionic equation simply cancel those ions that appear on bot sides of the equation. I see 2K^+(aq) and 2Cl^-(aq) on both sides so cancel those. What's left is the net ionic equation.
Ca^2+(aq) + [SO4]^2-(aq) ==> CaSO4(s)
The 2K^+ and 2Cl^- are called spectator ions since they do not enter into the reaction. The net ionic equation is the reaction.
Write the formula, complete ionic AND net ionic equation for the following,
a) CaCl2(aq) + K2SO4(aq)
b) Sr(OH)2(aq) + MgSO4
1 answer