K2SO4(aq) + Na2CO3(aq) ==> 2K^+(aq) + SO4^2-(aq) + 2Na^+(aq) + CO3^2-(aq)
The second one is done the same way. If there is
1. no gas
2. no ppt
3. no slightly ionized product
then you write a simple mixing o the ions. If one of the 3 occurs, there will be a reaction and you can write a net ionic equation.
For example,
AgNO3(aq) + NaCl(aq)==> AgCl(s) + NaNO3(aq) for which the net ionic equation is
Ag^+(aq) + Cl^-(aq) ==> AgCl(s)
hello i am having trouble writing these two ionic equations. could someone explain to me how to do that? 1.)K2SO4(aq) and Na2CO3(aq).Write the ionic equation.
2.)RbCl(aq) and KOH(aq).Write the ionic equation.
2 answers
2. Rb and K are in the same column 1 (group 1) which is soluble; meaning that they dissolved in a solution or solvent. The answer is just "noreaction" for the Ionic and Net equation