Write the expression without using the factorial symbol.

(n+1)!/(n-1)!

my work:
(n+1)!/((n+1)(n-1)!)

=1/(n-1)?

Thanks in advance.

4 answers

close

(n+1)!/(n-1)!
= (n+1)(n)(n-1)!/((n+1)(n-1)!
= n
hmm..the answer key says its n(n+1), maybe the answer key is wrong
wait, nevermind, I got it :)
thanks :P
You know what?

I looked at "my work" and assumed that was the starting question.

so here it goes once more

(n+1)!/(n-1)!
= (n+1)(n)(n-1)!/n-1)!
= n(n+1)

sorry
I should be more careful when reading questions.
Similar Questions
  1. write each expression without using the factorial symbol.1)(n-3)! ----- n! 2) (n+4)! ------- (n+2)!
    1. answers icon 2 answers
  2. def factorial(n):if n==1: else: return n* factorial(n-1) print("the factorial of ", 7, "is", factorial (7)) how could the
    1. answers icon 1 answer
    1. answers icon 1 answer
  3. Which code reflects the recursive case?(1 point) Responses else: return (x * factorial(x - 1)) else: return (x * factorial(x -
    1. answers icon 1 answer
more similar questions