Asked by sh
write each expression without using the factorial symbol.
1)(n-3)!
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n!
2) (n+4)!
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(n+2)!
1)(n-3)!
-----
n!
2) (n+4)!
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(n+2)!
Answers
Answered by
bobpursley
I will do one. Take the greater number, and expand it. for instance, the first
(n-3)!/(n*(n-1)(n-2)(n-3)!)
the (n-3)! terms divide out..
1/(n)(n-1)(n-2)
(n-3)!/(n*(n-1)(n-2)(n-3)!)
the (n-3)! terms divide out..
1/(n)(n-1)(n-2)
Answered by
sh
then the second one would be
(n+4)!/((n+1)(n+2)(n+3)(n+4)(n+2)!)
=
1/(n+1)(n+2)^2 (n+3) ?
(n+4)!/((n+1)(n+2)(n+3)(n+4)(n+2)!)
=
1/(n+1)(n+2)^2 (n+3) ?
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