3logx-6log(x^2+1)+log25
logx^3-log(x^2+1)+log25
logx^3+log25-log(x^2+1)^6
log(x^3*25/(x^2+1)^6))
write the expression as the logarithm of a single quantity
3[ln x-2 ln(x^2+1)]+2 ln 5
4 answers
wait, may I ask you what happened to ln?
it is the same thing bro log and ln
ln is log base e
3[ln x-2 ln(x^2+1)]+2 ln 5
ln a - ln b = ln (a/b)
n ln x = ln x^n
so
3 ln [ x/(x^2+1)^2] + ln 25
ln 25[ x/(x^2+1)^2]^3
so agree with Sam
3[ln x-2 ln(x^2+1)]+2 ln 5
ln a - ln b = ln (a/b)
n ln x = ln x^n
so
3 ln [ x/(x^2+1)^2] + ln 25
ln 25[ x/(x^2+1)^2]^3
so agree with Sam
1 answer