write the equilibrium constant expression for each reaction a.) NH3(g)+ CIF3(g)-><3HF(g) +1/2N(g) +1/2Cl2(g)

Answer 1

You need to use whole number coefficents to do this.

2NH3(g)+ 2CIF3(g)-><6HF(g) + N2(g) + Cl2(g)

Keq=[HF]⁶[N2][Cl2]/[NH3]²[ClF3]²