Is this just to keep me busy? What do you not understand about this?
Remember -dH is exothermic.
Large Keq means the reaction is favorable; small K means not very favorable.
Le Chatelier's Principle says when a system at equilibrium is disturbed, it will shift so as to undo what we've done to it. Add reagent, it shift AWAY from the addition, reducing reagent it shift TO it, increase in P shifts to side with fewer gas mols.
C6H12O6 (aq) = 602 (g) - 6CO2 (g) = 6H20 (l)
H -2837
A)Exo or endothermic?
B)write an expression for the equilibrium constant
C)Give the value of the equilibrium constant is very large, would this reaction be fast or slow?
D)effects of equilibrium if..
i. incerasing temp
ii. increasing pressure by decreasing volume
iii. decreasing concentration of oxygen
i.V. increasing the concentration of carbok dioxide
u. adding catalyst
1 answer