Write the equation of the linear function that passes through the points (2,-2) and (-3,13) y=___x +___

Answer 1

To find the equation of the linear function passing through the points (2,-2) and (-3,13), we need to first find the slope of the line using the two points.

The slope (m) of a line passing through the points (x1, y1) and (x2, y2) can be found using the formula:
m = (y2 - y1) / (x2 - x1)

Using our points (2,-2) and (-3,13):
m = (13 - (-2)) / (-3 - 2)
m = (13 + 2) / -5
m = 15 / -5
m = -3

Now that we have the slope, we can plug it into the point-slope form of a linear equation:
y - y1 = m(x - x1)

Using the point (2,-2):
y - (-2) = -3(x - 2)
y + 2 = -3x + 6
y = -3x + 4

Therefore, the equation of the linear function that passes through the points (2,-2) and (-3,13) is:
y = -3x + 4