write the equation of the linear function that passes through the point (2,1) and (5, 10)

Question

y=___x+____

Answer 1

First, let's find the slope of the line using the formula:

m = (y2 - y1) / (x2 - x1)

m = (10 - 1) / (5 - 2)
m = 9 / 3
m = 3

Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line:

y - y1 = m(x - x1)

Using the point (2,1):

y - 1 = 3(x - 2)
y - 1 = 3x - 6
y = 3x - 5

Therefore, the equation of the linear function that passes through the points (2,1) and (5,10) is:

y = 3x - 5

Answer 2

are you sure?

Answer 3

Apologies for the mistake. Let me correct that.

First, let's find the slope:

m = (y2 - y1) / (x2 - x1)
m = (10 - 1) / (5 - 2)
m = 9 / 3
m = 3

Now, using point-slope form with point (2,1):

y - 1 = 3(x - 2)
y - 1 = 3x - 6
y = 3x - 5

Therefore, the correct equation of the linear function passing through the points (2,1) and (5,10) is:

y = 3x - 5

Answer 4

write the equation of the linear function that passes through the point (2,2) and (0,3)
y=___x+____

Answer 5

First, let's find the slope of the line using the formula:

m = (y2 - y1) / (x2 - x1)

Given points (2, 2) and (0, 3):

m = (3 - 2) / (0 - 2)
m = 1 / -2
m = -1/2

Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line:

y - y1 = m(x - x1)

Using the point (2, 2):

y - 2 = (-1/2)(x - 2)
y - 2 = (-1/2)x + 1
y = (-1/2)x + 3

Therefore, the equation of the linear function that passes through the points (2, 2) and (0, 3) is:

y = (-1/2)x + 3