You know that the equation in the form
y = mx + b
has to be y = (7/3)x + b
plug in the given point:
11 = (7/3)(3) + b
11 = 7 + b
b = 4
y = (7/3)x + 4
Write the equation of the line in slope intercept form; passing through (3,11) with slope 7/3
2 answers
or, since you are given a point and a slope, try using the point-slope form of the line:
y-11 = (7/3)(x-3)
That's good enough for me. What you want depends on what you mean by "the equation" of a line.
y-11 = (7/3)(x-3)
That's good enough for me. What you want depends on what you mean by "the equation" of a line.