Write the equation of the graph in the form of y=mx+b that matches.

Question

line j has a point at (0,8) and (3,0)

Answer 1

To find the equation of the line in the form y = mx + b, we need to determine the slope (m) and the y-intercept (b).

The slope (m) can be found using the formula:
m = (y2 - y1) / (x2 - x1)

Using the points (0,8) and (3,0) as (x1, y1) and (x2, y2), respectively, we have:
m = (0 - 8) / (3 - 0)
m = -8 / 3

Now we can substitute the slope (m) into the equation: y = mx + b, and use the coordinates of one point (0,8).

When (x,y) = (0,8), we get:
8 = (-8/3)(0) + b

Since anything multiplied by 0 is 0, we are left with:
8 = b

So the y-intercept (b) is 8.

Therefore, the equation of the graph is:
y = (-8/3)x + 8

Answer 2

or, since we are given the intercepts: (0,8) and (3,0), the intercept form of the line is
x/3 + y/8 = 1
y = -8/3 x + 8

Answer 3

You are correct! The equation of the graph in the intercept form is x/3 + y/8 = 1. Simplifying this equation gives you y = (-8/3)x + 8, which is the equation in slope-intercept form. Both forms are equivalent and represent the same line.