Asked by Jessie
                Write an equation for a graph obtained by vertically shifting the graph of y = x^2 + 10 downward by 35 units,
followed by stretching the resulting graph by a factor of 19.6.
            
            
        followed by stretching the resulting graph by a factor of 19.6.
Answers
                    Answered by
            Jessie
            
    I found the answer to the question below, but I am not sure how it is supposed to differ from the one above?
Write an equation for a graph obtained by vertically stretching the
graph of y = x2 + 10 by a factor of 19.6, followed by a
vertical shift downward by 35 units.
    
Write an equation for a graph obtained by vertically stretching the
graph of y = x2 + 10 by a factor of 19.6, followed by a
vertical shift downward by 35 units.
                    Answered by
            Jessie
            
    (rewritten) I found the answer to the question below, but I am not sure how it is supposed to differ from the one above? 
Write an equation for a graph obtained by vertically stretching the
graph of y = x^2 + 10 by a factor of 19.6, followed by a
vertical shift downward by 35 units.
    
Write an equation for a graph obtained by vertically stretching the
graph of y = x^2 + 10 by a factor of 19.6, followed by a
vertical shift downward by 35 units.
                    Answered by
            Steve
            
    There's quite a difference between "shifting and stretching" and "stretching and shifting"
In the first case, the shift is also stretched.
For example, if you have a parabola y=x^2, if you stretch first, the graph still touches (0,0), no matter how far it is stretched. If it's then shifted, the stretched parabola is moved by that an=mount.
If it is shifted say, 5 units down, then after stretching by 3, the vertex is now 15 units down.
So, with that parabola,
stretch3-shift5: x^2 -> 3x^2 -> 3x^2-5
shift5-stretch3: x^2 -> x^2-5 -> 3(x^2-5) = 3x^2-15
Now apply that logic to your problem.
    
In the first case, the shift is also stretched.
For example, if you have a parabola y=x^2, if you stretch first, the graph still touches (0,0), no matter how far it is stretched. If it's then shifted, the stretched parabola is moved by that an=mount.
If it is shifted say, 5 units down, then after stretching by 3, the vertex is now 15 units down.
So, with that parabola,
stretch3-shift5: x^2 -> 3x^2 -> 3x^2-5
shift5-stretch3: x^2 -> x^2-5 -> 3(x^2-5) = 3x^2-15
Now apply that logic to your problem.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.