That is not an ellipse. You cannot have x^2 and y^2 terms of opposite sign, for an ellipse.
You have a hyperbola. Complete the squares for standard form.
Write the equation of the ellipse in standard form: 4x^2-9y^2-40x+36y+100=0
3 answers
okay, Thank you very much:)
wait, I still end up with the wrong answer. I end up with
4(x-5)^2/-120 - 9(y+2)^2=-120
9 can't go into -120
My procedure:
(4x^2-40x)-(9y^2+36y)=-100
4(x^2-10x +4)-9(y^2 +4 +4)=-100+ 4(4)-9(4)
4(x-5)^2-9(y+2)^2=-120
(x-5)^2/-30 - ? 9 can't go into -120 evenly
4(x-5)^2/-120 - 9(y+2)^2=-120
9 can't go into -120
My procedure:
(4x^2-40x)-(9y^2+36y)=-100
4(x^2-10x +4)-9(y^2 +4 +4)=-100+ 4(4)-9(4)
4(x-5)^2-9(y+2)^2=-120
(x-5)^2/-30 - ? 9 can't go into -120 evenly