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1. Find (-1+i)^1/3 2. Express 2(cos5pi/3 + isin5pi/3) in regular form. would this be correct: 1-√3i? 3. Find (2+4i)^3 in regular form. 4. Express 5(cos5pi/6 + isin5pi/6) in regular form. would this be correct?: -5√3/2 +5/2i?

solve x/x^2-4 - 1/x+2=2

Find (-1+i)^1/3 list steps

write 196x^2-256y^2+17=12561 in standard form, show work.

Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.

Parabola: Rewrite 3y^2 + 6y + 108x - 969=0 in standard form, show work.

What is the transverse axis of the following equation? 25x^2+250x-36y^2-576y=2579

Hyperbola: 25x^2+250x-36y^2-576y=2579 in standard form

1) expand (1+3x)^4 using the Binomial Theorem. 2) Use Pascal's Triangle to expand(x+2)^5 3)What is the third term of (a+b)^11?

Write the equation of the ellipse in standard form: 4x^2-9y^2-40x+36y+100=0

4x^2-9y^2-40x+36y+100=0 I still end up with the wrong answer. I end up with 4(x-5)^2/-120 - 9(y+2)^2=-120 9 can't go into -120 My procedure: (4x^2-40x)-(9y^2+36y)=-100 4(x^2-10x +4)-9(y^2 +4 +4)=-100+ 4(4)-9(4) 4(x-5)^2-9(y+2)^2=-120 (x-5)^2/-30 - ? 9 can...

find the following limit lim n->infinity 2+5n+4n^4/2n show steps please

solve 5^y=4^y+3.Round your answer to the nearest tenth.

just 17, that's what got me confused to

Thank you!:)

Don't answer, I understand it now.

Thank you steve

okay, Thank you very much:)

wait, I still end up with the wrong answer. I end up with 4(x-5)^2/-120 - 9(y+2)^2=-120 9 can't go into -120 My procedure: (4x^2-40x)-(9y^2+36y)=-100 4(x^2-10x +4)-9(y^2 +4 +4)=-100+ 4(4)-9(4) 4(x-5)^2-9(y+2)^2=-120 (x-5)^2/-30 - ? 9 can't go into -120 ev...

so its no limit which would just be infinity right?

I got 6.46

I did it a second time and got 1.98

Damon- yes, thank you

How did you get 18.6? on my calculator I typed in 3*log(4)/log(5)-log(4).Am I doing this wrong? solving it wrong?