A. (-4, 1), (2, 4).
m = (y2-y1)/(x2-x1) = (4-1)/(2+4) = 3/6 = 0.5.
Y = mx + b.
1 = 0.5(-4) + b,
b = 3. = y-intercept.
Eq: Y = (1/2)x + 3.
B. (2, -1), m = -1.
Y = mx + b.
-1 = (-1)2 + b,
b = ?
Eq:
C. (1, 1), y = 5.
Y = 5 for all values of x:
(0, 5), (1, 5).
m = (y2-y1)/(x2-x1) = (5-5)/(1-0) = 0/1 = 0.
Y = mx + b.
1 = 0*1 + b,
b = 1.
Eq: Y = 1.
D. m = -3, Yint. = (0, 8).
Y = mx + b.
8 = -3*0 + b,
b = 8.
Eq: Y = -3x + 8.
Write the equation of each line using the given information.
The points (−4,1) and (2,4)both lie on the line.
m=−1 and the point (2,−1) lies on the line.
It has the same slope as y=5 and passes through (1,1).
m=−3 and it has a y-intercept of (0,8)
plz help i don't get any of this.
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