Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y – 3 = (x + 2); (–2, 3)
A. Y+3= -3/8(X-2)
B.Y-3=-3/8(X+2)
C.Y-2=-3/8(X+3)
D. Y+3=3/8(X-2)
I am not sure how to do this problem...please help...
3 answers
This question was supposed to have a 8/3 after the = and before the (x+2)
if it was supposed to be
y – 3 = (8/3)(x + 2)
the it has slope 8/3, so the perpendicular has slope -3/8.
just plug in the point-slope form of the line:
(y-k) = m(x-h)
y-3 = -3/8 (x+2)
B
y – 3 = (8/3)(x + 2)
the it has slope 8/3, so the perpendicular has slope -3/8.
just plug in the point-slope form of the line:
(y-k) = m(x-h)
y-3 = -3/8 (x+2)
B
Thank you - I understand now
1 answer