Ask a New Question
Search
write the equation in vertex form, of a parabola with vertex (5, -1) and that passes through the point (6, 8)
1 answer
Y = a(x-h)^2 + k.
8 = a(6-5)^2 - 1,
8 = a - 1, a = 9.
Y = 9(x-5)^2 - 1.
Ask a New Question
or
answer this question
.
Similar Questions
Can you please help me with the below question:
The vertex of a parabola is located at (-12, -1). The parabola also passes
1 answer
write the vertex form equation of each parabola.
1) Vertex:(-5,8), Focus:(-21/4, 8) 2) Vertex:(-6,-9), Directrix: x= 47/8
4 answers
Suppose a parabola has an axis of symmetry at `x=-2,` a maximum height of `8`, and passes through the point `(-6,2)`. Write the
1 answer
The question was:
Suppose a parabola has vertex (5, –3) and also passes through the point (6, 1). Write the equation of the
1 answer
more similar questions