Question

Write the equation for the reaction associated with the Ka2 of sulfuric acid, H2SO4.

Write the equation for the reaction associated with the Kb2 of carbonate, CO32–.

Answer 1

1 H2SO4 ==> H^+ + HSO4^-
2 HSO4^ ==> H^+ + SO4^2-
1 is 100 ionized; therefore, there is no k1.
k2 = (H^+)(SO4^2-)/HSO4^-)

Do the same kind of thing with the hydrolysis of CO3^2-
1 CO3^2- + HOH ==> HCO3^- + OH^-
k1 = ....
2 HCO3^- + HOH ==> H2CO3 + OH^-
k2 = (H2CO3)(OH^-)/(HCO3^-) = ?

Answer 2

bob you are literally always wrong

Answer 3

DrBob222 is 100% correct. The acid will lose hydronium ions in water, whereas a base will gain hydronium ions in water; remember that the arrows must be pointing in both directions when writing these chemical equations due to equilibrium (strong acids and bases completely dissociate in water). It's actually not all that simple but best way to put it for those having difficulty understanding.

Answer 4

We Love you Bob, let the haters hate, they don't know what they're talking about

Answer 5

My Sapling grade is suffering, thanks Bob

Answer 6

I think Bob just put the equation in a different format than Sapling is asking for. I got
HSO4^- <--> SO4^2-(aq) + H^+(aq)
and
HCO3^-(aq) + H2O(l) <--> H2CO3(aq) + OH-(aq)

soooo he is kinda wrong?

Answer 7

hey bob seems like your going through it, don't worry we are too– thats exactly what bring us to this site. for all you sapling folks out there desperate for answer because you saved you homework for the last minute like myself. I have yet to find it ill keep you posted because I am having a hard time even typing this in, thanks.
good to hear from you bob

Answer 8

I didn't save it for last minute. I just don't understand how to solve it and instead i get a completely different format. Sorry Bob XD.

Answer 9

I love you bob

Answer 10

Yeah, his format is just wrong, i tried the other one and it worked

Answer 11

bob is doing his best