Asked by nancy
write the equation for a line in point-slope form and in slope-intercept form. parallel to 3x-4y=12 and passes through (8,3).
Answers
Answered by
MathMate
Point-slope form:
(y-y1)=m(x-x1)
Slope intercept form:
y=mx+b
b is the y-intercept, and m is the slope.
In the given case, m can be evalauated from the given parellel line by transforming it to slope intercept form:
3x-4y=12
y=(3/4)x - 3
so m=(3/4)
Point-slope form:
(x1,y1) = (8,3)
substitute (x1,y1) and m in the point slope form equation and voilà !
Expand the point slope form of the equation and normalize the coefficient of y to 1 to get the slope-intercept form of the equation.
Substitute (8,3) in both equations to make sure that each balances, i.e. the line passes through the given point.
(y-y1)=m(x-x1)
Slope intercept form:
y=mx+b
b is the y-intercept, and m is the slope.
In the given case, m can be evalauated from the given parellel line by transforming it to slope intercept form:
3x-4y=12
y=(3/4)x - 3
so m=(3/4)
Point-slope form:
(x1,y1) = (8,3)
substitute (x1,y1) and m in the point slope form equation and voilà !
Expand the point slope form of the equation and normalize the coefficient of y to 1 to get the slope-intercept form of the equation.
Substitute (8,3) in both equations to make sure that each balances, i.e. the line passes through the given point.
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