Standard form is usually Ax + By + C = 0 for a linear function.
For a quadratic it is usually Ay^2 + By + c = 0
you have a second variable. How does your textbook deal with this?
Write in standard form:
-2y^2+x-4y+1=0
5 answers
well this is supposed to be a parabola, and i just need help with factoring it into an standform equation that looks like this:
(x-h)^2=4p(y-k)
or
(y-k)^2=4p(x-h)
(x-h)^2=4p(y-k)
or
(y-k)^2=4p(x-h)
so, start chugging:
-2y^2+x-4y+1=0
-2y^2-4y = -x-1
-2(y^2+2) = -x-1
-2(y^2+2y+1) = -x-1 -2(1)
-2(y+1)^2 = -x-3
(y+1)^2 = 1/2(x+3)
-2y^2+x-4y+1=0
-2y^2-4y = -x-1
-2(y^2+2) = -x-1
-2(y^2+2y+1) = -x-1 -2(1)
-2(y+1)^2 = -x-3
(y+1)^2 = 1/2(x+3)
Thank you so much!
The STD form of a parabola that opens to the right.
X = 2y^2 + 4y - 1.
X = 2y^2 + 4y - 1.
3 answers