Write in point-slope form an equation of the line through the pair of points. (11, 1) and (5, 8)
What is an equation of the line in point-slope form?
a.) y - 1 = 7/6 (x - 11)
b.) x - 1 = -7/6 (y - 11)
c.) y = 7/6x + 83/6
d.)y - 1 = -7/6 (x - 11)
2 answers
I have to show my work as well, idk how to do this
slope = (8-1) / (5-11) = 7/-6 = -7/6
so
y = 1 -(7/6)(x-11)
or
y-1 = -7/6(x-11)
That starts at x = 11, y = 1 and marches down with a slope of -7/6
so
y = 1 -(7/6)(x-11)
or
y-1 = -7/6(x-11)
That starts at x = 11, y = 1 and marches down with a slope of -7/6