log ( a ^ n ) = n * log ( a )
log ( a * b ) = log ( a ) + log ( b )
log ( a / b ) = log ( a ) - log ( b )
log ( x + 1 ) + 2 log( 2 x + 1 )- log( x - 3 )=
log [( x + 1 ) * ( 2 x + 1 ) ^ 2 / ( x - 3 ) ]
Write as a single logarithm
log(x+1)+2log(2x+1)-log(x-3)
2 answers
I keep getting wrong answer, its not the same as the book :3
2 answers