Write an equation with the order pairs (9,6) and (10,5)

Answer 1

The equation of a straight line passing through the points (9,6) and (10,5) can be found using the point-slope formula: (y-y1) = m(x-x1), where m is the slope and (x1, y1) is one of the given points.

First, we find the slope (m) using the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) = (9,6) and (x2, y2) = (10,5):
m = (5-6) / (10-9) = -1 / 1 = -1

Now we can use one of the points (9,6) and the slope to find the equation of the line:
(y-6) = -1(x-9)
y-6 = -x + 9
y = -x + 9 + 6
y = -x + 15

Therefore, the equation of the line passing through the points (9,6) and (10,5) is y = -x + 15.