Write an equation of the line that passes through the point ( 8,3) and has the slope of 1/4
So, I think you would write it as Y=1/4x+B
and, you'd plug in 8 for the x, and 1 for the y.
So you'd get 1=1/4(4) + B
And you'd get.. 1=1+B
So, subtract one from each side
0=b
y=1/4x+B
Is my answer correct?
Thanks
4 answers
where does the 8 come into the problem at?
you would plug x=8 and y=3 into your y=1/4x+b formula..you eventually get the answer to be 1
yes y = (1/4) x + b
but
3 = (1/4)(8) + b
3 = 2 + b
b = 1
y = x/4 + 1
check
if x = 8
y = 8/4+ 1
y = 2 + 1
y = 3
yes (8,3)
but
3 = (1/4)(8) + b
3 = 2 + b
b = 1
y = x/4 + 1
check
if x = 8
y = 8/4+ 1
y = 2 + 1
y = 3
yes (8,3)
Thank you all.