I attempted this one. I would reverse to y = mx+b; So y = -9x+5. The slope is -9. I would then (y-y^1=m(x-x^1).
y - 9= 1/9(x-5)
Y = 1/9x+45/9. This is still wrong.
Write an equation of the line containing the given point and parallel to the given line. Express in y=mx+b. (-4, 9); 9x = 8y+5
3 answers
(-4 , 9), STD Form: 9x - 8y = 5.
m = -a/b = -9/-8 = 9/8.
y = mx + b = 9,
(9/8)*(-4) + b = 9,
-36/8 + b = 9,
-9/2 + b = 9,
b = 9 + 9/2,
b = 27/2.
Eq: y = (9/8)x + 27/2.
m = -a/b = -9/-8 = 9/8.
y = mx + b = 9,
(9/8)*(-4) + b = 9,
-36/8 + b = 9,
-9/2 + b = 9,
b = 9 + 9/2,
b = 27/2.
Eq: y = (9/8)x + 27/2.
Thank you!