Asked by Esther
write an equation of the line containing the point and perpendicular to the given line (4,-8); 2x+5y=4
I am having a very hard time, but I'm trying hard to study the steps for solving the problem.
Profoundly, thank you.
I am having a very hard time, but I'm trying hard to study the steps for solving the problem.
Profoundly, thank you.
Answers
Answered by
helper
Did you see the answer to your post below?
Post your work so I can see where you are having trouble.
Post your work so I can see where you are having trouble.
Answered by
Esther
Sorry, but, no, I didn't see the answer to my post. However,
(4,-8); 2x+5y=4 is?
y=-2x+4
y-8=1/2
y-8=1/2(x-4)
Again, I don't really know what to do after this. I may not even be followin the steps right. However, I would really appreacite your help. Thank you a million.
(4,-8); 2x+5y=4 is?
y=-2x+4
y-8=1/2
y-8=1/2(x-4)
Again, I don't really know what to do after this. I may not even be followin the steps right. However, I would really appreacite your help. Thank you a million.
Answered by
helper
2x + 5y = 4
Add -2x to both sides
5y = -2x + 4
divide both sides by 5
y = -2/5 y + 4/5
So, slope m = -2/5
Perpendicular lines, the slopes are negative reciprocals of each other.
Slope = -2/5
m1 * m2 = -1
-2/5 * m2 = -1
m2 = -1/(-2/5)
m2 = 5/2
Now you have to find b, for the equation of the perpendicular line.
y = mx + b
m = 5/2
y = 5/2 x + b
P(4, -8)
-8 = 5/2 (4) + b
-8 = 20/2 + b
-8 = 10 + b
-18 = b
y = 5/2 x + b
y = 5/2 + -18
y = 5/2 - 18
Follow these exact steps.
Add -2x to both sides
5y = -2x + 4
divide both sides by 5
y = -2/5 y + 4/5
So, slope m = -2/5
Perpendicular lines, the slopes are negative reciprocals of each other.
Slope = -2/5
m1 * m2 = -1
-2/5 * m2 = -1
m2 = -1/(-2/5)
m2 = 5/2
Now you have to find b, for the equation of the perpendicular line.
y = mx + b
m = 5/2
y = 5/2 x + b
P(4, -8)
-8 = 5/2 (4) + b
-8 = 20/2 + b
-8 = 10 + b
-18 = b
y = 5/2 x + b
y = 5/2 + -18
y = 5/2 - 18
Follow these exact steps.
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