Asked by Steve
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
y-3 = 8/3 (x+2); (-2,3)
y-3 = 8/3 (x+2); (-2,3)
Answers
Answered by
Reiny
slope of given line = 8/3
so slope of your new line = -3/8
through (-2,3)
y = 3 = (-3/8)(x+2)
since the original was written in that form, I assume the new one is to be in that same format.
so slope of your new line = -3/8
through (-2,3)
y = 3 = (-3/8)(x+2)
since the original was written in that form, I assume the new one is to be in that same format.
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