write the equation of the line with slope 2 that passes through the point (-1,5)

Answer 1

recall slope-point form:
y - y1 = m(x - x1)
where
m = slope
(x1, y1) = point on the line
thus,
y - 5 = 2(x - (-1))
y = 2(x + 1) + 5
y = 2x + 2 + 5
y = 2x + 7

hope this helps` :)

Answer 2

write y-3=-5(x+1) in slope-intercept form ?

Answer 3

Note that slope-intercept form is in the form
y = mx + b
where
m = slope
b = y-intercept
Thus,
y - 3 = -5(x + 1)
y = -5x - 5 + 3
y = -5x - 2