write an equation of the line containing the given point and parallel to the given line.
(5,-8); 9x-5y=2
2 answers
put the equation in slope intercept form. A line parallel will have the same slope.
9x-5y = 2; y = 9/5x -(2/5)
(using y=mx+c)
Slope of the given line = 9/5
hence the required line will have the same slope(9/5) since it is parallel.
Now putting the given point(5,-8)in y=mx+c; since it passes through (5,-8)
-8 = m * 5 + c where m= slope = 9/5
or -8 = (9/5)*5 + c
or c = -8-9; c = -17
Equation of the required line is
y = 9/5 x + (-17)
or 5y = 9x - 85
or 9x - 5y = 85 is the answer
(using y=mx+c)
Slope of the given line = 9/5
hence the required line will have the same slope(9/5) since it is parallel.
Now putting the given point(5,-8)in y=mx+c; since it passes through (5,-8)
-8 = m * 5 + c where m= slope = 9/5
or -8 = (9/5)*5 + c
or c = -8-9; c = -17
Equation of the required line is
y = 9/5 x + (-17)
or 5y = 9x - 85
or 9x - 5y = 85 is the answer
1 answer