Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y=mx+b (3,6); x+5y= 8
2 answers
anyone knows the answer to this question?
easiest way:
since the new equation is parallel to the given line x + 5y = 8
the new line will differ only in the constant.
New line: x + 5y = c
plug in the given point (3,6) ...
3 + 30 = c = 33
new line: x + 5y = 33
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What they want .....
given line: x + 5y = 8
5y = -x + 8
y = (-1/5)x + 8/5
so the slope of the line must be -1/5
new line: y = (-1/5)x + b , they must have the same slope
plug in the point (3,6)
6 = (-1/5)(3) + b
6 = -3/5 + b
b = 6 + 3/5 = 33/5
new equation : y = (-1/5)x + 33/5
which is the same as my equation done the easy way
since the new equation is parallel to the given line x + 5y = 8
the new line will differ only in the constant.
New line: x + 5y = c
plug in the given point (3,6) ...
3 + 30 = c = 33
new line: x + 5y = 33
-----------------------------------
What they want .....
given line: x + 5y = 8
5y = -x + 8
y = (-1/5)x + 8/5
so the slope of the line must be -1/5
new line: y = (-1/5)x + b , they must have the same slope
plug in the point (3,6)
6 = (-1/5)(3) + b
6 = -3/5 + b
b = 6 + 3/5 = 33/5
new equation : y = (-1/5)x + 33/5
which is the same as my equation done the easy way
1 answer