Write an equation of a line that is perpendicular to y = 3x + 3 and passes through (−6, 3).

Question

A. y equals negative one-third times x plus 1
B. y equals negative one-third times x minus 5
C. y = 3x + 21
D. y = 3x − 15

Answer 1

slope of y = 3x + 3 is 3, so the slope of your perpendicular is -1/3
using the given point (-6,3)

y - 3 = (-1/3)(x + 6)
times 3
3y - 9 = -x - 6
x + 3y = 3

or, if you insist ..
3y = -x + 3
y = (-1/3)x + 1