The point-slope form of a linear equation is:
y - y1 = m(x - x1)
Using the given point (3, -8) and slope m = -2:
y - (-8) = -2(x - 3)
y + 8 = -2x + 6
y = -2x - 2
Therefore, the equation in point-slope form is:
y = -2x - 2
Write an equation in the point-slope form for the line that goes through the point (3, -8) and has a slope of -2.
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