I would start it this way:
the vertex is (1,-8) , so we have
y = a(x-1)^2 - 8 , we don't know what a is
but (3,12) is on it, so
12 = a(3-1)^2 - 8 , you had that but messed up at the end
12 = a(4) - 8
20 = 4a
a = 5
y = 5(x-1)^2 - 8
Write an equation in standard form of the parabola that has the characteristics below.
Vertex at (1,-8); passing through the point (3,12)
So I started the problem and now I'm stuck as of what to do next.
Y=a(x-h)+k
12=a(3-1)^2-8
12=a(2)^2-8
12=4a-8
4=4a
1=a
2 answers
Insert <, >, or = to make the sentence true.
(6) -(10)
a.
>
b.
<
c.
=
(6) -(10)
a.
>
b.
<
c.
=