Asked by doeum juseyo
Write the equation in standard form using integers
(no fractions or decimals): 𝑦 = −2/3𝑥 − 1
6. Write an equation of the line that passes through
(2, -1) and is parallel to the graph of y = 5x – 2.
Write your final equation in slope-intercept form.
7. Write an equation of the line that passes through
(3, 5) and is perpendicular to the graph of y = –3x
+7. Write your final equation in slope-intercept
form.
8. Sketch a graph y = |x – 3| – 2 and describe the
translations.
(no fractions or decimals): 𝑦 = −2/3𝑥 − 1
6. Write an equation of the line that passes through
(2, -1) and is parallel to the graph of y = 5x – 2.
Write your final equation in slope-intercept form.
7. Write an equation of the line that passes through
(3, 5) and is perpendicular to the graph of y = –3x
+7. Write your final equation in slope-intercept
form.
8. Sketch a graph y = |x – 3| – 2 and describe the
translations.
Answers
Answered by
oobleck
do you know what the standard form is? First step should probably be to clear the fractions: 3y = -2x - 3
Now just rearrange the terms as needed
y = 5x – 2 has slope = 5
So, now you have a slope and a point, so start with the point-slope form:
y+1 = 5(x-2)
Now rearrange as needed.
y = –3x+7 has slope -3
So, you want a line with slope 1/3
Now follow the steps of #6
y = |x| is a v-shape, with vertex at (0,0)
y = |x – 3| – 2 is the same graph, shifted right 3 and down 2.
Now just rearrange the terms as needed
y = 5x – 2 has slope = 5
So, now you have a slope and a point, so start with the point-slope form:
y+1 = 5(x-2)
Now rearrange as needed.
y = –3x+7 has slope -3
So, you want a line with slope 1/3
Now follow the steps of #6
y = |x| is a v-shape, with vertex at (0,0)
y = |x – 3| – 2 is the same graph, shifted right 3 and down 2.
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