Question

Write an equation in standard form of the parabola that has the characteristics below.
Vertex at (1,-8); passing through the point (3,12)

So I started the problem and now I'm stuck as of what to do next.
Y=a(x-h)+k
12=a(3-1)^2-8
12=a(2)^2-8
12=4a-8
4=4a
1=a

Answer 1

I would start it this way:

the vertex is (1,-8) , so we have

y = a(x-1)^2 - 8 , we don't know what a is
but (3,12) is on it, so
12 = a(3-1)^2 - 8 , you had that but messed up at the end

12 = a(4) - 8
20 = 4a
a = 5


y = 5(x-1)^2 - 8

Answer 2

Insert <, >, or = to make the sentence true.

(6) -(10)

a.
>

b.
<

c.
=