The equation in standard form of a circle with center (0,0) and radius 4 is:
x^2 + y^2 = 16
Write an equation in standard form of a circle with the given center and radius. center (0,0); radius 4
3 answers
show your work please!
Sure, here's how to arrive at the equation:
The standard form of a circle equation is:
(x - h)^2 + (y - k)^2 = r^2
where (h, k) is the center of the circle and r is its radius.
In this case, we have:
center = (0,0)
radius = 4
So we can plug these values into the standard form equation and get:
(x - 0)^2 + (y - 0)^2 = 4^2
Simplifying, we get:
x^2 + y^2 = 16
This is the equation in standard form for a circle with center (0,0) and radius 4.
The standard form of a circle equation is:
(x - h)^2 + (y - k)^2 = r^2
where (h, k) is the center of the circle and r is its radius.
In this case, we have:
center = (0,0)
radius = 4
So we can plug these values into the standard form equation and get:
(x - 0)^2 + (y - 0)^2 = 4^2
Simplifying, we get:
x^2 + y^2 = 16
This is the equation in standard form for a circle with center (0,0) and radius 4.
2 answers