From the given information, you know that a = 4 and c = 8.
Using b^2 = c^2 - a^2, we get this:
b^2 = 8^2 - 4^2 = 64 - 16 = 48
Substituting 16 for a^2 and 48 for b^2 gives us this in standard form:
x^2/16 - y^2/48 = 1
I hope this helps.
Write an equation in standard form for the hyperbola with center (0,0), vertex(4,0) , and focus (8,0).
1) x^2/64-x^2/16=1
2)x^2/16-y^2/64=1
3)y^2/48-x^2/16=1
4)x^2/16-y^2/48=1
2 answers
Thank you again.