Since the new line is parallel to y=-x-2,
the new equation will differ only in the constant.
let it be y = -x + c
but (2,-2) is supposed to be on it, so
-2 = -2 + c
c = 0
new equation: y = -x
Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation (2-2) ;y=-x-2
Plz help
1 answer