write (27a^-3)^(-2/3) in simplest form.
solve log(6x+11)=2
please and thanks
I am not going to give you the answers. I will be happy to critique your work.
In the first, remember that (a^b)^c= a^bc
I am not looking for the answers.
And I told you:
I'm not quite sure what to do for the first, but this is what I tried to do:
(27a^-3)^(-2/3)
=the cubed root of (27a^-3)^-2
=the cubed root of 27^-2*a^6
and
what is the antilog?
but you didn't reply.